The woman is heterozygous for both colorblindness and for baldness. Chance of being a male is (1/2), chance of being color blind if male is (1/2), chance of being bald is (1/2), product of all of the above is (1/8). Two points for the right answer (1/8) and one point each for each of the component probabilies.
If we treat one chromosome as being A type and the homolog at a type, and the other chromosome as B type with the homolog as b type, it is apparent that there are four possible types of gametes produced by each sex (AB, Ab, aB ab).
Correct order:
b, c, a