AB 409
ab 391
aB 102
Ab 98
TOTAL 1000
Recombinant progeny = 200/1000 = 20% crossover types = 20 cM
E is in the middle in this case. This can be shown by calculating the pairwise map distances and also because the Dco classes differ from the parental classes by E.
Also determine the map distances between the genes (D to E, D to F, E to F) (1 pt. each).
D to E is (65 + 75 + 6 + 4) / 1000 = 150/1000 = 15 cM
E to F is (47 + 43 + 6 + 4) / 1000 = 100/ 1000 = 10 cM
D to F (the outside markers) is most accurately calculated by summing the two distances above, 10 + 15 = 25 cM
What is the value for the coefficient of coincidence? (1 pt.)
C = 10 observed DCOs / 15 expected = 2/3 or .67
15 expected is calculated as (.15)(.10)(1000) = 15
DEF 390
def 370
Def 65
dEF 75
DEf 47
deF 43
DeF 6
dEf 4
TOTAL 1000